9t^2-9t+2=0

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Solution for 9t^2-9t+2=0 equation: 



9t^2-9t+2=0

a = 9; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·9·2
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3}{2*9}=\frac{6}{18}
=1/3
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3}{2*9}=\frac{12}{18}
=2/3
$

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